Solve 2x² + 8x + 8 = 0
The solution of 2x² + 8x + 8 = 0 is x = -2 (a repeated root).
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = 8, c = 8.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is zero, so there is exactly one solution (a repeated root).
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solution:
- 8
Check by putting x = -2 back in: a·x² + b·x + c = 2·(4) + 8·(-2) + 8 = 0 ✓
LaTeX source of the formulas on this page
\[ 2x^2 + 8x + 8 = 0\ \Rightarrow\ x = -2 \]
\[ 2x^2 + 8x + 8 = 0 \]
\[ D = 8^2 - 4\cdot2\cdot8 = 64 - 64 = 0 \]
\[ 2\left(x + 2\right)\left(x + 2\right) = 0 \]
\[ x + 2 = 0 \Rightarrow x = -2 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{0}}{4} \]
\[ x = -2 \]The parabola y = 2x² + 8x + 8
| x | y |
|---|---|
| -5 | 18 |
| -4 | 8 |
| -3 | 2 |
| -2 | 0 |
| -1 | 2 |
| 0 | 8 |
| 1 | 18 |
Questions
What are the solutions of 2x² + 8x + 8 = 0?
The solution of 2x² + 8x + 8 = 0 is x = -2 (a repeated root).
Does 2x² + 8x + 8 = 0 factor?
Yes: 2(x+2)(x+2) = 0.
What is the vertex of y = 2x² + 8x + 8?
(-2, 0). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -4, product = c/a = 4.