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Solve 2x² + 6x - 8 = 0

The solutions of 2x² + 6x - 8 = 0 are x = 1 or x = -4.

x² +x += 0
2x2+6x−8=0⇒x=1, −42x^2 + 6x - 8 = 0 \Rightarrow x = 1,\ -4
Discriminant D = 100 · x ≈ 1, -4

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = 2x² + 6x - 8-6-5-4-3-2-1123-1010203040x = 1x = -4vertexy = 2x² + 6x - 8
Graph of y = 2x² + 6x - 8. The curve crosses the x-axis at x = 1 and x = -4; the vertex is at (-1.5, -12.5).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = 6, c = -8.

    2x2+6x−8=02x^2 + 6x - 8 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅2⋅(−8)=36+64=100D = 6^2 - 4\cdot2\cdot(-8) = 36 + 64 = 100
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    2(x−1)(x+4)=02\left(x - 1\right)\left(x + 4\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    x−1=0⇒x=1x+4=0⇒x=−4x - 1 = 0 \Rightarrow x = 1\qquad x + 4 = 0 \Rightarrow x = -4
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=−6±1004x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{100}}{4}
  7. 7

    Simplify to get the solutions:

    x=1orx=−4x = 1\quad\text{or}\quad x = -4
  8. 8

    Check by putting x = 1 back in: a·x² + b·x + c = 2·(1) + 6·(1) + (-8) = 0 ✓

LaTeX source of the formulas on this page
\[ 2x^2 + 6x - 8 = 0\ \Rightarrow\ x = 1,\ -4 \]
\[ 2x^2 + 6x - 8 = 0 \]
\[ D = 6^2 - 4\cdot2\cdot(-8) = 36 + 64 = 100 \]
\[ 2\left(x - 1\right)\left(x + 4\right) = 0 \]
\[ x - 1 = 0 \Rightarrow x = 1\qquad x + 4 = 0 \Rightarrow x = -4 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{100}}{4} \]
\[ x = 1\quad\text{or}\quad x = -4 \]

The parabola y = 2x² + 6x - 8

xy
-4.55.5
-3.5-4.5
-2.5-10.5
-1.5-12.5
-0.5-10.5
0.5-4.5
1.55.5

Questions

What are the solutions of 2x² + 6x - 8 = 0?

The solutions of 2x² + 6x - 8 = 0 are x = 1 or x = -4.

Does 2x² + 6x - 8 = 0 factor?

Yes: 2(x-1)(x+4) = 0.

What is the vertex of y = 2x² + 6x - 8?

(-3/2, -25/2). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -3, product = c/a = -4.

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