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Solve x² - 8x - 3 = 0

The solutions of x² - 8x - 3 = 0 are x = 4 + √19 or x = 4 - √19, that is x ≈ 8.3588989 and x ≈ -0.35889894.

x² +x += 0
x2−8x−3=0⇒x=4+19, 4−19x^2 - 8x - 3 = 0 \Rightarrow x = 4 + \sqrt{19},\ 4 - \sqrt{19}
Discriminant D = 76 · x ≈ 8.3589, -0.358899

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² - 8x - 3-2246810-20-10102030x = 8.3588989x = -0.35889894vertexy = x² - 8x - 3
Graph of y = x² - 8x - 3. The curve crosses the x-axis at x = 8.3588989 and x = -0.35889894; the vertex is at (4, -19).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = -8, c = -3.

    x2−8x−3=0x^2 - 8x - 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−8)2−4⋅1⋅(−3)=64+12=76D = (-8)^2 - 4\cdot1\cdot(-3) = 64 + 12 = 76
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=8±762x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{76}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=4+19orx=4−19x = 4 + \sqrt{19}\quad\text{or}\quad x = 4 - \sqrt{19}
  6. 6

    As decimals: x ≈ 8.3588989 and x ≈ -0.35889894.

  7. 7

    Check numerically: for x ≈ 8.3588989 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 - 8x - 3 = 0\ \Rightarrow\ x = 4 + \sqrt{19},\ 4 - \sqrt{19} \]
\[ x^2 - 8x - 3 = 0 \]
\[ D = (-8)^2 - 4\cdot1\cdot(-3) = 64 + 12 = 76 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{76}}{2} \]
\[ x = 4 + \sqrt{19}\quad\text{or}\quad x = 4 - \sqrt{19} \]

The parabola y = x² - 8x - 3

xy
1-10
2-15
3-18
4-19
5-18
6-15
7-10

Questions

What are the solutions of x² - 8x - 3 = 0?

The solutions of x² - 8x - 3 = 0 are x = 4 + √19 or x = 4 - √19, that is x ≈ 8.3588989 and x ≈ -0.35889894.

Does x² - 8x - 3 = 0 factor?

Not over the integers, because the discriminant 76 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² - 8x - 3?

(4, -19). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 8, product = c/a = -3.

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    Solve x² - 8x - 3 = 0: x = 4 + √19 or x = 4 - √19 (steps) | WordGPT