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Solve x² - 3x + 11 = 0

x² - 3x + 11 = 0 has no real solutions. The two complex solutions are x = (3 + √35 i)/2 and x = (3 - √35 i)/2.

x² +x += 0
x2−3x+11=0⇒x=3+35 i2, 3−35 i2 (complex)x^2 - 3x + 11 = 0 \Rightarrow x = \frac{3 + \sqrt{35}\, i}{2},\ \frac{3 - \sqrt{35}\, i}{2}\ \text{(complex)}
Discriminant D = -35

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² - 3x + 11-2-1123458101214161820222426vertexy = x² - 3x + 11
Graph of y = x² - 3x + 11. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.5, 8.75).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = -3, c = 11.

    x2−3x+11=0x^2 - 3x + 11 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−3)2−4⋅1⋅11=9−44=−35D = (-3)^2 - 4\cdot1\cdot11 = 9 - 44 = -35
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=3±−352x = \frac{-b \pm \sqrt{D}}{2a} = \frac{3 \pm \sqrt{-35}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=3+35 i2orx=3−35 i2x = \frac{3 + \sqrt{35}\, i}{2}\quad\text{or}\quad x = \frac{3 - \sqrt{35}\, i}{2}
LaTeX source of the formulas on this page
\[ x^2 - 3x + 11 = 0\ \Rightarrow\ x = \frac{3 + \sqrt{35}\, i}{2},\ \frac{3 - \sqrt{35}\, i}{2} \]
\[ x^2 - 3x + 11 = 0 \]
\[ D = (-3)^2 - 4\cdot1\cdot11 = 9 - 44 = -35 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{3 \pm \sqrt{-35}}{2} \]
\[ x = \frac{3 + \sqrt{35}\, i}{2}\quad\text{or}\quad x = \frac{3 - \sqrt{35}\, i}{2} \]

The parabola y = x² - 3x + 11

xy
-1.517.75
-0.512.75
0.59.75
1.58.75
2.59.75
3.512.75
4.517.75

Questions

What are the solutions of x² - 3x + 11 = 0?

x² - 3x + 11 = 0 has no real solutions. The two complex solutions are x = (3 + √35 i)/2 and x = (3 - √35 i)/2.

Does x² - 3x + 11 = 0 factor?

Not over the integers, because the discriminant -35 is negative. Use the quadratic formula.

What is the vertex of y = x² - 3x + 11?

(3/2, 35/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 3, product = c/a = 11.

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