Solve x² - 10x - 11 = 0
The solutions of x² - 10x - 11 = 0 are x = 11 or x = -1.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = -10, c = -11.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solutions:
- 8
Check by putting x = 11 back in: a·x² + b·x + c = 1·(121) + (-10)·(11) + (-11) = 0 ✓
LaTeX source of the formulas on this page
\[ x^2 - 10x - 11 = 0\ \Rightarrow\ x = 11,\ -1 \]
\[ x^2 - 10x - 11 = 0 \]
\[ D = (-10)^2 - 4\cdot1\cdot(-11) = 100 + 44 = 144 \]
\[ \left(x - 11\right)\left(x + 1\right) = 0 \]
\[ x - 11 = 0 \Rightarrow x = 11\qquad x + 1 = 0 \Rightarrow x = -1 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{144}}{2} \]
\[ x = 11\quad\text{or}\quad x = -1 \]The parabola y = x² - 10x - 11
| x | y |
|---|---|
| 2 | -27 |
| 3 | -32 |
| 4 | -35 |
| 5 | -36 |
| 6 | -35 |
| 7 | -32 |
| 8 | -27 |
Questions
What are the solutions of x² - 10x - 11 = 0?
The solutions of x² - 10x - 11 = 0 are x = 11 or x = -1.
Does x² - 10x - 11 = 0 factor?
Yes: (x-11)(x+1) = 0.
What is the vertex of y = x² - 10x - 11?
(5, -36). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = 10, product = c/a = -11.