Solve x² - 10x + 2 = 0
The solutions of x² - 10x + 2 = 0 are x = 5 + √23 or x = 5 - √23, that is x ≈ 9.7958315 and x ≈ 0.20416848.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = -10, c = 2.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ 9.7958315 and x ≈ 0.20416848.
- 7
Check numerically: for x ≈ 9.7958315 the left side is -1.4210855e-14 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ x^2 - 10x + 2 = 0\ \Rightarrow\ x = 5 + \sqrt{23},\ 5 - \sqrt{23} \]
\[ x^2 - 10x + 2 = 0 \]
\[ D = (-10)^2 - 4\cdot1\cdot2 = 100 - 8 = 92 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{92}}{2} \]
\[ x = 5 + \sqrt{23}\quad\text{or}\quad x = 5 - \sqrt{23} \]The parabola y = x² - 10x + 2
| x | y |
|---|---|
| 2 | -14 |
| 3 | -19 |
| 4 | -22 |
| 5 | -23 |
| 6 | -22 |
| 7 | -19 |
| 8 | -14 |
Questions
What are the solutions of x² - 10x + 2 = 0?
The solutions of x² - 10x + 2 = 0 are x = 5 + √23 or x = 5 - √23, that is x ≈ 9.7958315 and x ≈ 0.20416848.
Does x² - 10x + 2 = 0 factor?
Not over the integers, because the discriminant 92 is not a perfect square. Use the quadratic formula.
What is the vertex of y = x² - 10x + 2?
(5, -23). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = 10, product = c/a = 2.