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Solve x² + 8x + 3 = 0

The solutions of x² + 8x + 3 = 0 are x = -4 + √13 or x = -4 - √13, that is x ≈ -0.39444872 and x ≈ -7.6055513.

x² +x += 0
x2+8x+3=0⇒x=−4+13, −4−13x^2 + 8x + 3 = 0 \Rightarrow x = -4 + \sqrt{13},\ -4 - \sqrt{13}
Discriminant D = 52 · x ≈ -0.394449, -7.60555

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 8x + 3-10-8-6-4-22-101020x = -0.39444872x = -7.6055513vertexy = x² + 8x + 3
Graph of y = x² + 8x + 3. The curve crosses the x-axis at x = -0.39444872 and x = -7.6055513; the vertex is at (-4, -13).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 8, c = 3.

    x2+8x+3=0x^2 + 8x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅1⋅3=64−12=52D = 8^2 - 4\cdot1\cdot3 = 64 - 12 = 52
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±522x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{52}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+13orx=−4−13x = -4 + \sqrt{13}\quad\text{or}\quad x = -4 - \sqrt{13}
  6. 6

    As decimals: x ≈ -0.39444872 and x ≈ -7.6055513.

  7. 7

    Check numerically: for x ≈ -0.39444872 the left side is -1.3322676e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 8x + 3 = 0\ \Rightarrow\ x = -4 + \sqrt{13},\ -4 - \sqrt{13} \]
\[ x^2 + 8x + 3 = 0 \]
\[ D = 8^2 - 4\cdot1\cdot3 = 64 - 12 = 52 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{52}}{2} \]
\[ x = -4 + \sqrt{13}\quad\text{or}\quad x = -4 - \sqrt{13} \]

The parabola y = x² + 8x + 3

xy
-7-4
-6-9
-5-12
-4-13
-3-12
-2-9
-1-4

Questions

What are the solutions of x² + 8x + 3 = 0?

The solutions of x² + 8x + 3 = 0 are x = -4 + √13 or x = -4 - √13, that is x ≈ -0.39444872 and x ≈ -7.6055513.

Does x² + 8x + 3 = 0 factor?

Not over the integers, because the discriminant 52 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 8x + 3?

(-4, -13). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8, product = c/a = 3.

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    Solve x² + 8x + 3 = 0: x = -4 + √13 or x = -4 - √13 (steps) | WordGPT