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Solve x² + 8x + 11 = 0

The solutions of x² + 8x + 11 = 0 are x = -4 + √5 or x = -4 - √5, that is x ≈ -1.763932 and x ≈ -6.236068.

x² +x += 0
x2+8x+11=0⇒x=−4+5, −4−5x^2 + 8x + 11 = 0 \Rightarrow x = -4 + \sqrt{5},\ -4 - \sqrt{5}
Discriminant D = 20 · x ≈ -1.76393, -6.23607

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 8x + 11-8-7-6-5-4-3-2-1-551015x = -1.763932x = -6.236068vertexy = x² + 8x + 11
Graph of y = x² + 8x + 11. The curve crosses the x-axis at x = -1.763932 and x = -6.236068; the vertex is at (-4, -5).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 8, c = 11.

    x2+8x+11=0x^2 + 8x + 11 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅1⋅11=64−44=20D = 8^2 - 4\cdot1\cdot11 = 64 - 44 = 20
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±202x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{20}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+5orx=−4−5x = -4 + \sqrt{5}\quad\text{or}\quad x = -4 - \sqrt{5}
  6. 6

    As decimals: x ≈ -1.763932 and x ≈ -6.236068.

  7. 7

    Check numerically: for x ≈ -1.763932 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 8x + 11 = 0\ \Rightarrow\ x = -4 + \sqrt{5},\ -4 - \sqrt{5} \]
\[ x^2 + 8x + 11 = 0 \]
\[ D = 8^2 - 4\cdot1\cdot11 = 64 - 44 = 20 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{20}}{2} \]
\[ x = -4 + \sqrt{5}\quad\text{or}\quad x = -4 - \sqrt{5} \]

The parabola y = x² + 8x + 11

xy
-74
-6-1
-5-4
-4-5
-3-4
-2-1
-14

Questions

What are the solutions of x² + 8x + 11 = 0?

The solutions of x² + 8x + 11 = 0 are x = -4 + √5 or x = -4 - √5, that is x ≈ -1.763932 and x ≈ -6.236068.

Does x² + 8x + 11 = 0 factor?

Not over the integers, because the discriminant 20 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 8x + 11?

(-4, -5). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8, product = c/a = 11.

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    Solve x² + 8x + 11 = 0: x = -4 + √5 or x = -4 - √5 (steps) | WordGPT