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Solve x² + 6x - 9 = 0

The solutions of x² + 6x - 9 = 0 are x = -3 + 3√2 or x = -3 - 3√2, that is x ≈ 1.2426407 and x ≈ -7.2426407.

x² +x += 0
x2+6x−9=0⇒x=−3+32, −3−32x^2 + 6x - 9 = 0 \Rightarrow x = -3 + 3\sqrt{2},\ -3 - 3\sqrt{2}
Discriminant D = 72 · x ≈ 1.24264, -7.24264

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 6x - 9-8-6-4-22-20-10102030x = 1.2426407x = -7.2426407vertexy = x² + 6x - 9
Graph of y = x² + 6x - 9. The curve crosses the x-axis at x = 1.2426407 and x = -7.2426407; the vertex is at (-3, -18).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 6, c = -9.

    x2+6x−9=0x^2 + 6x - 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅1⋅(−9)=36+36=72D = 6^2 - 4\cdot1\cdot(-9) = 36 + 36 = 72
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−6±722x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{72}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−3+32orx=−3−32x = -3 + 3\sqrt{2}\quad\text{or}\quad x = -3 - 3\sqrt{2}
  6. 6

    As decimals: x ≈ 1.2426407 and x ≈ -7.2426407.

  7. 7

    Check numerically: for x ≈ 1.2426407 the left side is -3.5527137e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 6x - 9 = 0\ \Rightarrow\ x = -3 + 3\sqrt{2},\ -3 - 3\sqrt{2} \]
\[ x^2 + 6x - 9 = 0 \]
\[ D = 6^2 - 4\cdot1\cdot(-9) = 36 + 36 = 72 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{72}}{2} \]
\[ x = -3 + 3\sqrt{2}\quad\text{or}\quad x = -3 - 3\sqrt{2} \]

The parabola y = x² + 6x - 9

xy
-6-9
-5-14
-4-17
-3-18
-2-17
-1-14
0-9

Questions

What are the solutions of x² + 6x - 9 = 0?

The solutions of x² + 6x - 9 = 0 are x = -3 + 3√2 or x = -3 - 3√2, that is x ≈ 1.2426407 and x ≈ -7.2426407.

Does x² + 6x - 9 = 0 factor?

Not over the integers, because the discriminant 72 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 6x - 9?

(-3, -18). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -6, product = c/a = -9.

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    Solve x² + 6x - 9 = 0: x = -3 + 3√2 or x = -3 - 3√2 (steps) | WordGPT