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Solve x² + 6x - 5 = 0

The solutions of x² + 6x - 5 = 0 are x = -3 + √14 or x = -3 - √14, that is x ≈ 0.74165739 and x ≈ -6.7416574.

x² +x += 0
x2+6x−5=0⇒x=−3+14, −3−14x^2 + 6x - 5 = 0 \Rightarrow x = -3 + \sqrt{14},\ -3 - \sqrt{14}
Discriminant D = 56 · x ≈ 0.741657, -6.74166

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 6x - 5-8-6-4-22-101020x = 0.74165739x = -6.7416574vertexy = x² + 6x - 5
Graph of y = x² + 6x - 5. The curve crosses the x-axis at x = 0.74165739 and x = -6.7416574; the vertex is at (-3, -14).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 6, c = -5.

    x2+6x−5=0x^2 + 6x - 5 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅1⋅(−5)=36+20=56D = 6^2 - 4\cdot1\cdot(-5) = 36 + 20 = 56
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−6±562x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{56}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−3+14orx=−3−14x = -3 + \sqrt{14}\quad\text{or}\quad x = -3 - \sqrt{14}
  6. 6

    As decimals: x ≈ 0.74165739 and x ≈ -6.7416574.

  7. 7

    Check numerically: for x ≈ 0.74165739 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 6x - 5 = 0\ \Rightarrow\ x = -3 + \sqrt{14},\ -3 - \sqrt{14} \]
\[ x^2 + 6x - 5 = 0 \]
\[ D = 6^2 - 4\cdot1\cdot(-5) = 36 + 20 = 56 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{56}}{2} \]
\[ x = -3 + \sqrt{14}\quad\text{or}\quad x = -3 - \sqrt{14} \]

The parabola y = x² + 6x - 5

xy
-6-5
-5-10
-4-13
-3-14
-2-13
-1-10
0-5

Questions

What are the solutions of x² + 6x - 5 = 0?

The solutions of x² + 6x - 5 = 0 are x = -3 + √14 or x = -3 - √14, that is x ≈ 0.74165739 and x ≈ -6.7416574.

Does x² + 6x - 5 = 0 factor?

Not over the integers, because the discriminant 56 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 6x - 5?

(-3, -14). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -6, product = c/a = -5.

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    Solve x² + 6x - 5 = 0: x = -3 + √14 or x = -3 - √14 (steps) | WordGPT