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Solve x² + 6x - 12 = 0

The solutions of x² + 6x - 12 = 0 are x = -3 + √21 or x = -3 - √21, that is x ≈ 1.5825757 and x ≈ -7.5825757.

x² +x += 0
x2+6x−12=0⇒x=−3+21, −3−21x^2 + 6x - 12 = 0 \Rightarrow x = -3 + \sqrt{21},\ -3 - \sqrt{21}
Discriminant D = 84 · x ≈ 1.58258, -7.58258

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = x² + 6x - 12-10-8-6-4-224-20-10102030x = 1.5825757x = -7.5825757vertexy = x² + 6x - 12
Graph of y = x² + 6x - 12. The curve crosses the x-axis at x = 1.5825757 and x = -7.5825757; the vertex is at (-3, -21).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 6, c = -12.

    x2+6x−12=0x^2 + 6x - 12 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅1⋅(−12)=36+48=84D = 6^2 - 4\cdot1\cdot(-12) = 36 + 48 = 84
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−6±842x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{84}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−3+21orx=−3−21x = -3 + \sqrt{21}\quad\text{or}\quad x = -3 - \sqrt{21}
  6. 6

    As decimals: x ≈ 1.5825757 and x ≈ -7.5825757.

  7. 7

    Check numerically: for x ≈ 1.5825757 the left side is -1.7763568e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 6x - 12 = 0\ \Rightarrow\ x = -3 + \sqrt{21},\ -3 - \sqrt{21} \]
\[ x^2 + 6x - 12 = 0 \]
\[ D = 6^2 - 4\cdot1\cdot(-12) = 36 + 48 = 84 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{84}}{2} \]
\[ x = -3 + \sqrt{21}\quad\text{or}\quad x = -3 - \sqrt{21} \]

The parabola y = x² + 6x - 12

xy
-6-12
-5-17
-4-20
-3-21
-2-20
-1-17
0-12

Questions

What are the solutions of x² + 6x - 12 = 0?

The solutions of x² + 6x - 12 = 0 are x = -3 + √21 or x = -3 - √21, that is x ≈ 1.5825757 and x ≈ -7.5825757.

Does x² + 6x - 12 = 0 factor?

Not over the integers, because the discriminant 84 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 6x - 12?

(-3, -21). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -6, product = c/a = -12.

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    Solve x² + 6x - 12 = 0: x = -3 + √21 or x = -3 - √21 (steps) | WordGPT