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Solve x² + 6x + 2 = 0

The solutions of x² + 6x + 2 = 0 are x = -3 + √7 or x = -3 - √7, that is x ≈ -0.35424869 and x ≈ -5.6457513.

x² +x += 0
x2+6x+2=0⇒x=−3+7, −3−7x^2 + 6x + 2 = 0 \Rightarrow x = -3 + \sqrt{7},\ -3 - \sqrt{7}
Discriminant D = 28 · x ≈ -0.354249, -5.64575

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 6x + 2-8-7-6-5-4-3-2-112-10-55101520x = -0.35424869x = -5.6457513vertexy = x² + 6x + 2
Graph of y = x² + 6x + 2. The curve crosses the x-axis at x = -0.35424869 and x = -5.6457513; the vertex is at (-3, -7).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 6, c = 2.

    x2+6x+2=0x^2 + 6x + 2 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅1⋅2=36−8=28D = 6^2 - 4\cdot1\cdot2 = 36 - 8 = 28
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−6±282x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{28}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−3+7orx=−3−7x = -3 + \sqrt{7}\quad\text{or}\quad x = -3 - \sqrt{7}
  6. 6

    As decimals: x ≈ -0.35424869 and x ≈ -5.6457513.

  7. 7

    Check numerically: for x ≈ -0.35424869 the left side is 6.6613381e-16 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 6x + 2 = 0\ \Rightarrow\ x = -3 + \sqrt{7},\ -3 - \sqrt{7} \]
\[ x^2 + 6x + 2 = 0 \]
\[ D = 6^2 - 4\cdot1\cdot2 = 36 - 8 = 28 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{28}}{2} \]
\[ x = -3 + \sqrt{7}\quad\text{or}\quad x = -3 - \sqrt{7} \]

The parabola y = x² + 6x + 2

xy
-62
-5-3
-4-6
-3-7
-2-6
-1-3
02

Questions

What are the solutions of x² + 6x + 2 = 0?

The solutions of x² + 6x + 2 = 0 are x = -3 + √7 or x = -3 - √7, that is x ≈ -0.35424869 and x ≈ -5.6457513.

Does x² + 6x + 2 = 0 factor?

Not over the integers, because the discriminant 28 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 6x + 2?

(-3, -7). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -6, product = c/a = 2.

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    Solve x² + 6x + 2 = 0: x = -3 + √7 or x = -3 - √7 (steps) | WordGPT