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Solve x² + 10x + 8 = 0

The solutions of x² + 10x + 8 = 0 are x = -5 + √17 or x = -5 - √17, that is x ≈ -0.87689437 and x ≈ -9.1231056.

x² +x += 0
x2+10x+8=0⇒x=−5+17, −5−17x^2 + 10x + 8 = 0 \Rightarrow x = -5 + \sqrt{17},\ -5 - \sqrt{17}
Discriminant D = 68 · x ≈ -0.876894, -9.12311

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 10x + 8-10-8-6-4-2-20-10102030x = -0.87689437x = -9.1231056vertexy = x² + 10x + 8
Graph of y = x² + 10x + 8. The curve crosses the x-axis at x = -0.87689437 and x = -9.1231056; the vertex is at (-5, -17).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 10, c = 8.

    x2+10x+8=0x^2 + 10x + 8 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=102−4⋅1⋅8=100−32=68D = 10^2 - 4\cdot1\cdot8 = 100 - 32 = 68
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−10±682x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-10 \pm \sqrt{68}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−5+17orx=−5−17x = -5 + \sqrt{17}\quad\text{or}\quad x = -5 - \sqrt{17}
  6. 6

    As decimals: x ≈ -0.87689437 and x ≈ -9.1231056.

  7. 7

    Check numerically: for x ≈ -0.87689437 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 10x + 8 = 0\ \Rightarrow\ x = -5 + \sqrt{17},\ -5 - \sqrt{17} \]
\[ x^2 + 10x + 8 = 0 \]
\[ D = 10^2 - 4\cdot1\cdot8 = 100 - 32 = 68 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-10 \pm \sqrt{68}}{2} \]
\[ x = -5 + \sqrt{17}\quad\text{or}\quad x = -5 - \sqrt{17} \]

The parabola y = x² + 10x + 8

xy
-8-8
-7-13
-6-16
-5-17
-4-16
-3-13
-2-8

Questions

What are the solutions of x² + 10x + 8 = 0?

The solutions of x² + 10x + 8 = 0 are x = -5 + √17 or x = -5 - √17, that is x ≈ -0.87689437 and x ≈ -9.1231056.

Does x² + 10x + 8 = 0 factor?

Not over the integers, because the discriminant 68 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 10x + 8?

(-5, -17). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -10, product = c/a = 8.

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    Solve x² + 10x + 8 = 0: x = -5 + √17 or x = -5 - √17 (steps) | WordGPT