Solve 9x + 9 = ā72
The solution of 9x + 9 = ā72 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 9 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 9 = -72\ \Rightarrow\ x = -9 \]
\[ 9x + 9 = -72 \]
\[ 9x + 9 - 9 = -72 - 9 \ \Rightarrow\ 9x = -81 \]
\[ \frac{9x}{9} = \frac{-81}{9} \ \Rightarrow\ x = -9 \]
\[ 9\cdot(-9) + 9 = -81 + 9 = -72 \checkmark \]Trying values of x in 9x + 9 = ā72
| x | 9x + 9 | Equals -72? |
|---|---|---|
| -11 | -90 | no |
| -10 | -81 | no |
| -9 | -72 | yes |
| -8 | -63 | no |
| -7 | -54 | no |
Questions
What is x in 9x + 9 = ā72?
The solution of 9x + 9 = ā72 is x = -9.
How do you solve 9x + 9 = ā72?
Subtract 9 from both sides to get 9x = -81, then divide both sides by 9 to get x = -9.
How do I check the answer?
Replace x by -9: 9(-9) + 9 = -72, which is -72.