Solve 9x + 7 = ā65
The solution of 9x + 7 = ā65 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 7 = -65\ \Rightarrow\ x = -8 \]
\[ 9x + 7 = -65 \]
\[ 9x + 7 - 7 = -65 - 7 \ \Rightarrow\ 9x = -72 \]
\[ \frac{9x}{9} = \frac{-72}{9} \ \Rightarrow\ x = -8 \]
\[ 9\cdot(-8) + 7 = -72 + 7 = -65 \checkmark \]Trying values of x in 9x + 7 = ā65
| x | 9x + 7 | Equals -65? |
|---|---|---|
| -10 | -83 | no |
| -9 | -74 | no |
| -8 | -65 | yes |
| -7 | -56 | no |
| -6 | -47 | no |
Questions
What is x in 9x + 7 = ā65?
The solution of 9x + 7 = ā65 is x = -8.
How do you solve 9x + 7 = ā65?
Subtract 7 from both sides to get 9x = -72, then divide both sides by 9 to get x = -8.
How do I check the answer?
Replace x by -8: 9(-8) + 7 = -65, which is -65.