Solve 9x + 5 = ā67
The solution of 9x + 5 = ā67 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 5 = -67\ \Rightarrow\ x = -8 \]
\[ 9x + 5 = -67 \]
\[ 9x + 5 - 5 = -67 - 5 \ \Rightarrow\ 9x = -72 \]
\[ \frac{9x}{9} = \frac{-72}{9} \ \Rightarrow\ x = -8 \]
\[ 9\cdot(-8) + 5 = -72 + 5 = -67 \checkmark \]Trying values of x in 9x + 5 = ā67
| x | 9x + 5 | Equals -67? |
|---|---|---|
| -10 | -85 | no |
| -9 | -76 | no |
| -8 | -67 | yes |
| -7 | -58 | no |
| -6 | -49 | no |
Questions
What is x in 9x + 5 = ā67?
The solution of 9x + 5 = ā67 is x = -8.
How do you solve 9x + 5 = ā67?
Subtract 5 from both sides to get 9x = -72, then divide both sides by 9 to get x = -8.
How do I check the answer?
Replace x by -8: 9(-8) + 5 = -67, which is -67.