Solve 9x + 5 = ā40
The solution of 9x + 5 = ā40 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 5 = -40\ \Rightarrow\ x = -5 \]
\[ 9x + 5 = -40 \]
\[ 9x + 5 - 5 = -40 - 5 \ \Rightarrow\ 9x = -45 \]
\[ \frac{9x}{9} = \frac{-45}{9} \ \Rightarrow\ x = -5 \]
\[ 9\cdot(-5) + 5 = -45 + 5 = -40 \checkmark \]Trying values of x in 9x + 5 = ā40
| x | 9x + 5 | Equals -40? |
|---|---|---|
| -7 | -58 | no |
| -6 | -49 | no |
| -5 | -40 | yes |
| -4 | -31 | no |
| -3 | -22 | no |
Questions
What is x in 9x + 5 = ā40?
The solution of 9x + 5 = ā40 is x = -5.
How do you solve 9x + 5 = ā40?
Subtract 5 from both sides to get 9x = -45, then divide both sides by 9 to get x = -5.
How do I check the answer?
Replace x by -5: 9(-5) + 5 = -40, which is -40.