Solve 9x + 11 = ā79
The solution of 9x + 11 = ā79 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 11 = -79\ \Rightarrow\ x = -10 \]
\[ 9x + 11 = -79 \]
\[ 9x + 11 - 11 = -79 - 11 \ \Rightarrow\ 9x = -90 \]
\[ \frac{9x}{9} = \frac{-90}{9} \ \Rightarrow\ x = -10 \]
\[ 9\cdot(-10) + 11 = -90 + 11 = -79 \checkmark \]Trying values of x in 9x + 11 = ā79
| x | 9x + 11 | Equals -79? |
|---|---|---|
| -12 | -97 | no |
| -11 | -88 | no |
| -10 | -79 | yes |
| -9 | -70 | no |
| -8 | -61 | no |
Questions
What is x in 9x + 11 = ā79?
The solution of 9x + 11 = ā79 is x = -10.
How do you solve 9x + 11 = ā79?
Subtract 11 from both sides to get 9x = -90, then divide both sides by 9 to get x = -10.
How do I check the answer?
Replace x by -10: 9(-10) + 11 = -79, which is -79.