Solve 9x + 11 = 20
The solution of 9x + 11 = 20 is x = 1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 1 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 11 = 20\ \Rightarrow\ x = 1 \]
\[ 9x + 11 = 20 \]
\[ 9x + 11 - 11 = 20 - 11 \ \Rightarrow\ 9x = 9 \]
\[ \frac{9x}{9} = \frac{9}{9} \ \Rightarrow\ x = 1 \]
\[ 9\cdot1 + 11 = 9 + 11 = 20 \checkmark \]Trying values of x in 9x + 11 = 20
| x | 9x + 11 | Equals 20? |
|---|---|---|
| -1 | 2 | no |
| 0 | 11 | no |
| 1 | 20 | yes |
| 2 | 29 | no |
| 3 | 38 | no |
Questions
What is x in 9x + 11 = 20?
The solution of 9x + 11 = 20 is x = 1.
How do you solve 9x + 11 = 20?
Subtract 11 from both sides to get 9x = 9, then divide both sides by 9 to get x = 1.
How do I check the answer?
Replace x by 1: 9(1) + 11 = 20, which is 20.