Solve 9x + 10 = 118
The solution of 9x + 10 = 118 is x = 12.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 12 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 10 = 118\ \Rightarrow\ x = 12 \]
\[ 9x + 10 = 118 \]
\[ 9x + 10 - 10 = 118 - 10 \ \Rightarrow\ 9x = 108 \]
\[ \frac{9x}{9} = \frac{108}{9} \ \Rightarrow\ x = 12 \]
\[ 9\cdot12 + 10 = 108 + 10 = 118 \checkmark \]Trying values of x in 9x + 10 = 118
| x | 9x + 10 | Equals 118? |
|---|---|---|
| 10 | 100 | no |
| 11 | 109 | no |
| 12 | 118 | yes |
| 13 | 127 | no |
| 14 | 136 | no |
Questions
What is x in 9x + 10 = 118?
The solution of 9x + 10 = 118 is x = 12.
How do you solve 9x + 10 = 118?
Subtract 10 from both sides to get 9x = 108, then divide both sides by 9 to get x = 12.
How do I check the answer?
Replace x by 12: 9(12) + 10 = 118, which is 118.