Solve 9x + 1 = ā80
The solution of 9x + 1 = ā80 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 1 = -80\ \Rightarrow\ x = -9 \]
\[ 9x + 1 = -80 \]
\[ 9x + 1 - 1 = -80 - 1 \ \Rightarrow\ 9x = -81 \]
\[ \frac{9x}{9} = \frac{-81}{9} \ \Rightarrow\ x = -9 \]
\[ 9\cdot(-9) + 1 = -81 + 1 = -80 \checkmark \]Trying values of x in 9x + 1 = ā80
| x | 9x + 1 | Equals -80? |
|---|---|---|
| -11 | -98 | no |
| -10 | -89 | no |
| -9 | -80 | yes |
| -8 | -71 | no |
| -7 | -62 | no |
Questions
What is x in 9x + 1 = ā80?
The solution of 9x + 1 = ā80 is x = -9.
How do you solve 9x + 1 = ā80?
Subtract 1 from both sides to get 9x = -81, then divide both sides by 9 to get x = -9.
How do I check the answer?
Replace x by -9: 9(-9) + 1 = -80, which is -80.