Solve 9x + 1 = 82
The solution of 9x + 1 = 82 is x = 9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 9 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 1 = 82\ \Rightarrow\ x = 9 \]
\[ 9x + 1 = 82 \]
\[ 9x + 1 - 1 = 82 - 1 \ \Rightarrow\ 9x = 81 \]
\[ \frac{9x}{9} = \frac{81}{9} \ \Rightarrow\ x = 9 \]
\[ 9\cdot9 + 1 = 81 + 1 = 82 \checkmark \]Trying values of x in 9x + 1 = 82
| x | 9x + 1 | Equals 82? |
|---|---|---|
| 7 | 64 | no |
| 8 | 73 | no |
| 9 | 82 | yes |
| 10 | 91 | no |
| 11 | 100 | no |
Questions
What is x in 9x + 1 = 82?
The solution of 9x + 1 = 82 is x = 9.
How do you solve 9x + 1 = 82?
Subtract 1 from both sides to get 9x = 81, then divide both sides by 9 to get x = 9.
How do I check the answer?
Replace x by 9: 9(9) + 1 = 82, which is 82.