Solve 9x + 1 = 28
The solution of 9x + 1 = 28 is x = 3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 3 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 1 = 28\ \Rightarrow\ x = 3 \]
\[ 9x + 1 = 28 \]
\[ 9x + 1 - 1 = 28 - 1 \ \Rightarrow\ 9x = 27 \]
\[ \frac{9x}{9} = \frac{27}{9} \ \Rightarrow\ x = 3 \]
\[ 9\cdot3 + 1 = 27 + 1 = 28 \checkmark \]Trying values of x in 9x + 1 = 28
| x | 9x + 1 | Equals 28? |
|---|---|---|
| 1 | 10 | no |
| 2 | 19 | no |
| 3 | 28 | yes |
| 4 | 37 | no |
| 5 | 46 | no |
Questions
What is x in 9x + 1 = 28?
The solution of 9x + 1 = 28 is x = 3.
How do you solve 9x + 1 = 28?
Subtract 1 from both sides to get 9x = 27, then divide both sides by 9 to get x = 3.
How do I check the answer?
Replace x by 3: 9(3) + 1 = 28, which is 28.