Solve 9x + 1 = 118
The solution of 9x + 1 = 118 is x = 13.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 13 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 1 = 118\ \Rightarrow\ x = 13 \]
\[ 9x + 1 = 118 \]
\[ 9x + 1 - 1 = 118 - 1 \ \Rightarrow\ 9x = 117 \]
\[ \frac{9x}{9} = \frac{117}{9} \ \Rightarrow\ x = 13 \]
\[ 9\cdot13 + 1 = 117 + 1 = 118 \checkmark \]Trying values of x in 9x + 1 = 118
| x | 9x + 1 | Equals 118? |
|---|---|---|
| 11 | 100 | no |
| 12 | 109 | no |
| 13 | 118 | yes |
| 14 | 127 | no |
| 15 | 136 | no |
Questions
What is x in 9x + 1 = 118?
The solution of 9x + 1 = 118 is x = 13.
How do you solve 9x + 1 = 118?
Subtract 1 from both sides to get 9x = 117, then divide both sides by 9 to get x = 13.
How do I check the answer?
Replace x by 13: 9(13) + 1 = 118, which is 118.