Solve 9x ā 15 = 147
The solution of 9x ā 15 = 147 is x = 18.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 15 to both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 18 back into the equation.
LaTeX source of the formulas on this page
\[ 9x - 15 = 147\ \Rightarrow\ x = 18 \]
\[ 9x - 15 = 147 \]
\[ 9x - 15 + 15 = 147 + 15 \ \Rightarrow\ 9x = 162 \]
\[ \frac{9x}{9} = \frac{162}{9} \ \Rightarrow\ x = 18 \]
\[ 9\cdot18 - 15 = 162 - 15 = 147 \checkmark \]Trying values of x in 9x ā 15 = 147
| x | 9x ā 15 | Equals 147? |
|---|---|---|
| 16 | 129 | no |
| 17 | 138 | no |
| 18 | 147 | yes |
| 19 | 156 | no |
| 20 | 165 | no |
Questions
What is x in 9x ā 15 = 147?
The solution of 9x ā 15 = 147 is x = 18.
How do you solve 9x ā 15 = 147?
Add 15 to both sides to get 9x = 162, then divide both sides by 9 to get x = 18.
How do I check the answer?
Replace x by 18: 9(18) ā 15 = 147, which is 147.