Solve 9x ā 1 = 152
The solution of 9x ā 1 = 152 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 1 to both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 9x - 1 = 152\ \Rightarrow\ x = 17 \]
\[ 9x - 1 = 152 \]
\[ 9x - 1 + 1 = 152 + 1 \ \Rightarrow\ 9x = 153 \]
\[ \frac{9x}{9} = \frac{153}{9} \ \Rightarrow\ x = 17 \]
\[ 9\cdot17 - 1 = 153 - 1 = 152 \checkmark \]Trying values of x in 9x ā 1 = 152
| x | 9x ā 1 | Equals 152? |
|---|---|---|
| 15 | 134 | no |
| 16 | 143 | no |
| 17 | 152 | yes |
| 18 | 161 | no |
| 19 | 170 | no |
Questions
What is x in 9x ā 1 = 152?
The solution of 9x ā 1 = 152 is x = 17.
How do you solve 9x ā 1 = 152?
Add 1 to both sides to get 9x = 153, then divide both sides by 9 to get x = 17.
How do I check the answer?
Replace x by 17: 9(17) ā 1 = 152, which is 152.