Solve 8x + 9 = 41
The solution of 8x + 9 = 41 is x = 4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 9 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 4 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 9 = 41\ \Rightarrow\ x = 4 \]
\[ 8x + 9 = 41 \]
\[ 8x + 9 - 9 = 41 - 9 \ \Rightarrow\ 8x = 32 \]
\[ \frac{8x}{8} = \frac{32}{8} \ \Rightarrow\ x = 4 \]
\[ 8\cdot4 + 9 = 32 + 9 = 41 \checkmark \]Trying values of x in 8x + 9 = 41
| x | 8x + 9 | Equals 41? |
|---|---|---|
| 2 | 25 | no |
| 3 | 33 | no |
| 4 | 41 | yes |
| 5 | 49 | no |
| 6 | 57 | no |
Questions
What is x in 8x + 9 = 41?
The solution of 8x + 9 = 41 is x = 4.
How do you solve 8x + 9 = 41?
Subtract 9 from both sides to get 8x = 32, then divide both sides by 8 to get x = 4.
How do I check the answer?
Replace x by 4: 8(4) + 9 = 41, which is 41.