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Solve 8x + 8 = āˆ’32

The solution of 8x + 8 = āˆ’32 is x = -5.

The lines y = 8x + 8 and y = -32 meet at x = -5-10-8-6-4-2-80-60-40-2020x = -5y = 8x + 8y = -32
The lines y = 8x + 8 and y = -32 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+8=āˆ’328x + 8 = -32
  2. 2

    Subtract 8 from both sides:

    8x+8āˆ’8=āˆ’32āˆ’8 ⇒ 8x=āˆ’408x + 8 - 8 = -32 - 8 \ \Rightarrow\ 8x = -40
  3. 3

    Divide both sides by 8:

    8x8=āˆ’408 ⇒ x=āˆ’5\frac{8x}{8} = \frac{-40}{8} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    8ā‹…(āˆ’5)+8=āˆ’40+8=āˆ’32āœ“8\cdot(-5) + 8 = -40 + 8 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 8 = -32\ \Rightarrow\ x = -5 \]
\[ 8x + 8 = -32 \]
\[ 8x + 8 - 8 = -32 - 8 \ \Rightarrow\ 8x = -40 \]
\[ \frac{8x}{8} = \frac{-40}{8} \ \Rightarrow\ x = -5 \]
\[ 8\cdot(-5) + 8 = -40 + 8 = -32 \checkmark \]

Trying values of x in 8x + 8 = āˆ’32

x8x + 8Equals -32?
-7-48no
-6-40no
-5-32yes
-4-24no
-3-16no

Questions

What is x in 8x + 8 = āˆ’32?

The solution of 8x + 8 = āˆ’32 is x = -5.

How do you solve 8x + 8 = āˆ’32?

Subtract 8 from both sides to get 8x = -40, then divide both sides by 8 to get x = -5.

How do I check the answer?

Replace x by -5: 8(-5) + 8 = -32, which is -32.

Similar equations

    Solve 8x + 8 = āˆ’32: x = -5 (steps and check) | WordGPT