Solve 8x + 8 = 128
The solution of 8x + 8 = 128 is x = 15.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 15 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 8 = 128\ \Rightarrow\ x = 15 \]
\[ 8x + 8 = 128 \]
\[ 8x + 8 - 8 = 128 - 8 \ \Rightarrow\ 8x = 120 \]
\[ \frac{8x}{8} = \frac{120}{8} \ \Rightarrow\ x = 15 \]
\[ 8\cdot15 + 8 = 120 + 8 = 128 \checkmark \]Trying values of x in 8x + 8 = 128
| x | 8x + 8 | Equals 128? |
|---|---|---|
| 13 | 112 | no |
| 14 | 120 | no |
| 15 | 128 | yes |
| 16 | 136 | no |
| 17 | 144 | no |
Questions
What is x in 8x + 8 = 128?
The solution of 8x + 8 = 128 is x = 15.
How do you solve 8x + 8 = 128?
Subtract 8 from both sides to get 8x = 120, then divide both sides by 8 to get x = 15.
How do I check the answer?
Replace x by 15: 8(15) + 8 = 128, which is 128.