Solve 8x + 7 = ā33
The solution of 8x + 7 = ā33 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 7 = -33\ \Rightarrow\ x = -5 \]
\[ 8x + 7 = -33 \]
\[ 8x + 7 - 7 = -33 - 7 \ \Rightarrow\ 8x = -40 \]
\[ \frac{8x}{8} = \frac{-40}{8} \ \Rightarrow\ x = -5 \]
\[ 8\cdot(-5) + 7 = -40 + 7 = -33 \checkmark \]Trying values of x in 8x + 7 = ā33
| x | 8x + 7 | Equals -33? |
|---|---|---|
| -7 | -49 | no |
| -6 | -41 | no |
| -5 | -33 | yes |
| -4 | -25 | no |
| -3 | -17 | no |
Questions
What is x in 8x + 7 = ā33?
The solution of 8x + 7 = ā33 is x = -5.
How do you solve 8x + 7 = ā33?
Subtract 7 from both sides to get 8x = -40, then divide both sides by 8 to get x = -5.
How do I check the answer?
Replace x by -5: 8(-5) + 7 = -33, which is -33.