Solve 8x + 7 = 63
The solution of 8x + 7 = 63 is x = 7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 7 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 7 = 63\ \Rightarrow\ x = 7 \]
\[ 8x + 7 = 63 \]
\[ 8x + 7 - 7 = 63 - 7 \ \Rightarrow\ 8x = 56 \]
\[ \frac{8x}{8} = \frac{56}{8} \ \Rightarrow\ x = 7 \]
\[ 8\cdot7 + 7 = 56 + 7 = 63 \checkmark \]Trying values of x in 8x + 7 = 63
| x | 8x + 7 | Equals 63? |
|---|---|---|
| 5 | 47 | no |
| 6 | 55 | no |
| 7 | 63 | yes |
| 8 | 71 | no |
| 9 | 79 | no |
Questions
What is x in 8x + 7 = 63?
The solution of 8x + 7 = 63 is x = 7.
How do you solve 8x + 7 = 63?
Subtract 7 from both sides to get 8x = 56, then divide both sides by 8 to get x = 7.
How do I check the answer?
Replace x by 7: 8(7) + 7 = 63, which is 63.