Solve 8x + 5 = ā27
The solution of 8x + 5 = ā27 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 5 = -27\ \Rightarrow\ x = -4 \]
\[ 8x + 5 = -27 \]
\[ 8x + 5 - 5 = -27 - 5 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) + 5 = -32 + 5 = -27 \checkmark \]Trying values of x in 8x + 5 = ā27
| x | 8x + 5 | Equals -27? |
|---|---|---|
| -6 | -43 | no |
| -5 | -35 | no |
| -4 | -27 | yes |
| -3 | -19 | no |
| -2 | -11 | no |
Questions
What is x in 8x + 5 = ā27?
The solution of 8x + 5 = ā27 is x = -4.
How do you solve 8x + 5 = ā27?
Subtract 5 from both sides to get 8x = -32, then divide both sides by 8 to get x = -4.
How do I check the answer?
Replace x by -4: 8(-4) + 5 = -27, which is -27.