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Solve 8x + 5 = āˆ’11

The solution of 8x + 5 = āˆ’11 is x = -2.

The lines y = 8x + 5 and y = -11 meet at x = -2-8-6-4-224-60-40-202040x = -2y = 8x + 5y = -11
The lines y = 8x + 5 and y = -11 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+5=āˆ’118x + 5 = -11
  2. 2

    Subtract 5 from both sides:

    8x+5āˆ’5=āˆ’11āˆ’5 ⇒ 8x=āˆ’168x + 5 - 5 = -11 - 5 \ \Rightarrow\ 8x = -16
  3. 3

    Divide both sides by 8:

    8x8=āˆ’168 ⇒ x=āˆ’2\frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    8ā‹…(āˆ’2)+5=āˆ’16+5=āˆ’11āœ“8\cdot(-2) + 5 = -16 + 5 = -11 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 5 = -11\ \Rightarrow\ x = -2 \]
\[ 8x + 5 = -11 \]
\[ 8x + 5 - 5 = -11 - 5 \ \Rightarrow\ 8x = -16 \]
\[ \frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2 \]
\[ 8\cdot(-2) + 5 = -16 + 5 = -11 \checkmark \]

Trying values of x in 8x + 5 = āˆ’11

x8x + 5Equals -11?
-4-27no
-3-19no
-2-11yes
-1-3no
05no

Questions

What is x in 8x + 5 = āˆ’11?

The solution of 8x + 5 = āˆ’11 is x = -2.

How do you solve 8x + 5 = āˆ’11?

Subtract 5 from both sides to get 8x = -16, then divide both sides by 8 to get x = -2.

How do I check the answer?

Replace x by -2: 8(-2) + 5 = -11, which is -11.

Similar equations

    Solve 8x + 5 = āˆ’11: x = -2 (steps and check) | WordGPT