Solve 8x + 2 = ā78
The solution of 8x + 2 = ā78 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 2 = -78\ \Rightarrow\ x = -10 \]
\[ 8x + 2 = -78 \]
\[ 8x + 2 - 2 = -78 - 2 \ \Rightarrow\ 8x = -80 \]
\[ \frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10 \]
\[ 8\cdot(-10) + 2 = -80 + 2 = -78 \checkmark \]Trying values of x in 8x + 2 = ā78
| x | 8x + 2 | Equals -78? |
|---|---|---|
| -12 | -94 | no |
| -11 | -86 | no |
| -10 | -78 | yes |
| -9 | -70 | no |
| -8 | -62 | no |
Questions
What is x in 8x + 2 = ā78?
The solution of 8x + 2 = ā78 is x = -10.
How do you solve 8x + 2 = ā78?
Subtract 2 from both sides to get 8x = -80, then divide both sides by 8 to get x = -10.
How do I check the answer?
Replace x by -10: 8(-10) + 2 = -78, which is -78.