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Solve 8x + 2 = āˆ’62

The solution of 8x + 2 = āˆ’62 is x = -8.

The lines y = 8x + 2 and y = -62 meet at x = -8-14-12-10-8-6-4-2-100-80-60-40-20x = -8y = 8x + 2y = -62
The lines y = 8x + 2 and y = -62 meet at x = -8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+2=āˆ’628x + 2 = -62
  2. 2

    Subtract 2 from both sides:

    8x+2āˆ’2=āˆ’62āˆ’2 ⇒ 8x=āˆ’648x + 2 - 2 = -62 - 2 \ \Rightarrow\ 8x = -64
  3. 3

    Divide both sides by 8:

    8x8=āˆ’648 ⇒ x=āˆ’8\frac{8x}{8} = \frac{-64}{8} \ \Rightarrow\ x = -8
  4. 4

    Check: put x = -8 back into the equation.

    8ā‹…(āˆ’8)+2=āˆ’64+2=āˆ’62āœ“8\cdot(-8) + 2 = -64 + 2 = -62 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 2 = -62\ \Rightarrow\ x = -8 \]
\[ 8x + 2 = -62 \]
\[ 8x + 2 - 2 = -62 - 2 \ \Rightarrow\ 8x = -64 \]
\[ \frac{8x}{8} = \frac{-64}{8} \ \Rightarrow\ x = -8 \]
\[ 8\cdot(-8) + 2 = -64 + 2 = -62 \checkmark \]

Trying values of x in 8x + 2 = āˆ’62

x8x + 2Equals -62?
-10-78no
-9-70no
-8-62yes
-7-54no
-6-46no

Questions

What is x in 8x + 2 = āˆ’62?

The solution of 8x + 2 = āˆ’62 is x = -8.

How do you solve 8x + 2 = āˆ’62?

Subtract 2 from both sides to get 8x = -64, then divide both sides by 8 to get x = -8.

How do I check the answer?

Replace x by -8: 8(-8) + 2 = -62, which is -62.

Similar equations

    Solve 8x + 2 = āˆ’62: x = -8 (steps and check) | WordGPT