Solve 8x + 2 = ā62
The solution of 8x + 2 = ā62 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 2 = -62\ \Rightarrow\ x = -8 \]
\[ 8x + 2 = -62 \]
\[ 8x + 2 - 2 = -62 - 2 \ \Rightarrow\ 8x = -64 \]
\[ \frac{8x}{8} = \frac{-64}{8} \ \Rightarrow\ x = -8 \]
\[ 8\cdot(-8) + 2 = -64 + 2 = -62 \checkmark \]Trying values of x in 8x + 2 = ā62
| x | 8x + 2 | Equals -62? |
|---|---|---|
| -10 | -78 | no |
| -9 | -70 | no |
| -8 | -62 | yes |
| -7 | -54 | no |
| -6 | -46 | no |
Questions
What is x in 8x + 2 = ā62?
The solution of 8x + 2 = ā62 is x = -8.
How do you solve 8x + 2 = ā62?
Subtract 2 from both sides to get 8x = -64, then divide both sides by 8 to get x = -8.
How do I check the answer?
Replace x by -8: 8(-8) + 2 = -62, which is -62.