Solve 8x + 2 = 122
The solution of 8x + 2 = 122 is x = 15.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 15 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 2 = 122\ \Rightarrow\ x = 15 \]
\[ 8x + 2 = 122 \]
\[ 8x + 2 - 2 = 122 - 2 \ \Rightarrow\ 8x = 120 \]
\[ \frac{8x}{8} = \frac{120}{8} \ \Rightarrow\ x = 15 \]
\[ 8\cdot15 + 2 = 120 + 2 = 122 \checkmark \]Trying values of x in 8x + 2 = 122
| x | 8x + 2 | Equals 122? |
|---|---|---|
| 13 | 106 | no |
| 14 | 114 | no |
| 15 | 122 | yes |
| 16 | 130 | no |
| 17 | 138 | no |
Questions
What is x in 8x + 2 = 122?
The solution of 8x + 2 = 122 is x = 15.
How do you solve 8x + 2 = 122?
Subtract 2 from both sides to get 8x = 120, then divide both sides by 8 to get x = 15.
How do I check the answer?
Replace x by 15: 8(15) + 2 = 122, which is 122.