Solve 8x + 15 = ā41
The solution of 8x + 15 = ā41 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 15 = -41\ \Rightarrow\ x = -7 \]
\[ 8x + 15 = -41 \]
\[ 8x + 15 - 15 = -41 - 15 \ \Rightarrow\ 8x = -56 \]
\[ \frac{8x}{8} = \frac{-56}{8} \ \Rightarrow\ x = -7 \]
\[ 8\cdot(-7) + 15 = -56 + 15 = -41 \checkmark \]Trying values of x in 8x + 15 = ā41
| x | 8x + 15 | Equals -41? |
|---|---|---|
| -9 | -57 | no |
| -8 | -49 | no |
| -7 | -41 | yes |
| -6 | -33 | no |
| -5 | -25 | no |
Questions
What is x in 8x + 15 = ā41?
The solution of 8x + 15 = ā41 is x = -7.
How do you solve 8x + 15 = ā41?
Subtract 15 from both sides to get 8x = -56, then divide both sides by 8 to get x = -7.
How do I check the answer?
Replace x by -7: 8(-7) + 15 = -41, which is -41.