Solve 8x + 12 = ā52
The solution of 8x + 12 = ā52 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 12 = -52\ \Rightarrow\ x = -8 \]
\[ 8x + 12 = -52 \]
\[ 8x + 12 - 12 = -52 - 12 \ \Rightarrow\ 8x = -64 \]
\[ \frac{8x}{8} = \frac{-64}{8} \ \Rightarrow\ x = -8 \]
\[ 8\cdot(-8) + 12 = -64 + 12 = -52 \checkmark \]Trying values of x in 8x + 12 = ā52
| x | 8x + 12 | Equals -52? |
|---|---|---|
| -10 | -68 | no |
| -9 | -60 | no |
| -8 | -52 | yes |
| -7 | -44 | no |
| -6 | -36 | no |
Questions
What is x in 8x + 12 = ā52?
The solution of 8x + 12 = ā52 is x = -8.
How do you solve 8x + 12 = ā52?
Subtract 12 from both sides to get 8x = -64, then divide both sides by 8 to get x = -8.
How do I check the answer?
Replace x by -8: 8(-8) + 12 = -52, which is -52.