Solve 8x + 12 = ā36
The solution of 8x + 12 = ā36 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 12 = -36\ \Rightarrow\ x = -6 \]
\[ 8x + 12 = -36 \]
\[ 8x + 12 - 12 = -36 - 12 \ \Rightarrow\ 8x = -48 \]
\[ \frac{8x}{8} = \frac{-48}{8} \ \Rightarrow\ x = -6 \]
\[ 8\cdot(-6) + 12 = -48 + 12 = -36 \checkmark \]Trying values of x in 8x + 12 = ā36
| x | 8x + 12 | Equals -36? |
|---|---|---|
| -8 | -52 | no |
| -7 | -44 | no |
| -6 | -36 | yes |
| -5 | -28 | no |
| -4 | -20 | no |
Questions
What is x in 8x + 12 = ā36?
The solution of 8x + 12 = ā36 is x = -6.
How do you solve 8x + 12 = ā36?
Subtract 12 from both sides to get 8x = -48, then divide both sides by 8 to get x = -6.
How do I check the answer?
Replace x by -6: 8(-6) + 12 = -36, which is -36.