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Solve 8x + 12 = āˆ’20

The solution of 8x + 12 = āˆ’20 is x = -4.

The lines y = 8x + 12 and y = -20 meet at x = -4-10-8-6-4-22-60-40-2020x = -4y = 8x + 12y = -20
The lines y = 8x + 12 and y = -20 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+12=āˆ’208x + 12 = -20
  2. 2

    Subtract 12 from both sides:

    8x+12āˆ’12=āˆ’20āˆ’12 ⇒ 8x=āˆ’328x + 12 - 12 = -20 - 12 \ \Rightarrow\ 8x = -32
  3. 3

    Divide both sides by 8:

    8x8=āˆ’328 ⇒ x=āˆ’4\frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    8ā‹…(āˆ’4)+12=āˆ’32+12=āˆ’20āœ“8\cdot(-4) + 12 = -32 + 12 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 12 = -20\ \Rightarrow\ x = -4 \]
\[ 8x + 12 = -20 \]
\[ 8x + 12 - 12 = -20 - 12 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) + 12 = -32 + 12 = -20 \checkmark \]

Trying values of x in 8x + 12 = āˆ’20

x8x + 12Equals -20?
-6-36no
-5-28no
-4-20yes
-3-12no
-2-4no

Questions

What is x in 8x + 12 = āˆ’20?

The solution of 8x + 12 = āˆ’20 is x = -4.

How do you solve 8x + 12 = āˆ’20?

Subtract 12 from both sides to get 8x = -32, then divide both sides by 8 to get x = -4.

How do I check the answer?

Replace x by -4: 8(-4) + 12 = -20, which is -20.

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    Solve 8x + 12 = āˆ’20: x = -4 (steps and check) | WordGPT