Solve 8x + 12 = 28
The solution of 8x + 12 = 28 is x = 2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 2 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 12 = 28\ \Rightarrow\ x = 2 \]
\[ 8x + 12 = 28 \]
\[ 8x + 12 - 12 = 28 - 12 \ \Rightarrow\ 8x = 16 \]
\[ \frac{8x}{8} = \frac{16}{8} \ \Rightarrow\ x = 2 \]
\[ 8\cdot2 + 12 = 16 + 12 = 28 \checkmark \]Trying values of x in 8x + 12 = 28
| x | 8x + 12 | Equals 28? |
|---|---|---|
| 0 | 12 | no |
| 1 | 20 | no |
| 2 | 28 | yes |
| 3 | 36 | no |
| 4 | 44 | no |
Questions
What is x in 8x + 12 = 28?
The solution of 8x + 12 = 28 is x = 2.
How do you solve 8x + 12 = 28?
Subtract 12 from both sides to get 8x = 16, then divide both sides by 8 to get x = 2.
How do I check the answer?
Replace x by 2: 8(2) + 12 = 28, which is 28.