Solve 8x + 1 = 97
The solution of 8x + 1 = 97 is x = 12.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 12 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 1 = 97\ \Rightarrow\ x = 12 \]
\[ 8x + 1 = 97 \]
\[ 8x + 1 - 1 = 97 - 1 \ \Rightarrow\ 8x = 96 \]
\[ \frac{8x}{8} = \frac{96}{8} \ \Rightarrow\ x = 12 \]
\[ 8\cdot12 + 1 = 96 + 1 = 97 \checkmark \]Trying values of x in 8x + 1 = 97
| x | 8x + 1 | Equals 97? |
|---|---|---|
| 10 | 81 | no |
| 11 | 89 | no |
| 12 | 97 | yes |
| 13 | 105 | no |
| 14 | 113 | no |
Questions
What is x in 8x + 1 = 97?
The solution of 8x + 1 = 97 is x = 12.
How do you solve 8x + 1 = 97?
Subtract 1 from both sides to get 8x = 96, then divide both sides by 8 to get x = 12.
How do I check the answer?
Replace x by 12: 8(12) + 1 = 97, which is 97.