Solve 8x + 1 = 17
The solution of 8x + 1 = 17 is x = 2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 2 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 1 = 17\ \Rightarrow\ x = 2 \]
\[ 8x + 1 = 17 \]
\[ 8x + 1 - 1 = 17 - 1 \ \Rightarrow\ 8x = 16 \]
\[ \frac{8x}{8} = \frac{16}{8} \ \Rightarrow\ x = 2 \]
\[ 8\cdot2 + 1 = 16 + 1 = 17 \checkmark \]Trying values of x in 8x + 1 = 17
| x | 8x + 1 | Equals 17? |
|---|---|---|
| 0 | 1 | no |
| 1 | 9 | no |
| 2 | 17 | yes |
| 3 | 25 | no |
| 4 | 33 | no |
Questions
What is x in 8x + 1 = 17?
The solution of 8x + 1 = 17 is x = 2.
How do you solve 8x + 1 = 17?
Subtract 1 from both sides to get 8x = 16, then divide both sides by 8 to get x = 2.
How do I check the answer?
Replace x by 2: 8(2) + 1 = 17, which is 17.