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Solve 8x āˆ’ 8 = 0

The solution of 8x āˆ’ 8 = 0 is x = 1.

The lines y = 8x āˆ’ 8 and y = 0 meet at x = 1-4-2246-40-202040x = 1y = 8x āˆ’ 8y = 0
The lines y = 8x āˆ’ 8 and y = 0 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’8=08x - 8 = 0
  2. 2

    Add 8 to both sides:

    8xāˆ’8+8=0+8 ⇒ 8x=88x - 8 + 8 = 0 + 8 \ \Rightarrow\ 8x = 8
  3. 3

    Divide both sides by 8:

    8x8=88 ⇒ x=1\frac{8x}{8} = \frac{8}{8} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    8ā‹…1āˆ’8=8āˆ’8=0āœ“8\cdot1 - 8 = 8 - 8 = 0 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 8 = 0\ \Rightarrow\ x = 1 \]
\[ 8x - 8 = 0 \]
\[ 8x - 8 + 8 = 0 + 8 \ \Rightarrow\ 8x = 8 \]
\[ \frac{8x}{8} = \frac{8}{8} \ \Rightarrow\ x = 1 \]
\[ 8\cdot1 - 8 = 8 - 8 = 0 \checkmark \]

Trying values of x in 8x āˆ’ 8 = 0

x8x āˆ’ 8Equals 0?
-1-16no
0-8no
10yes
28no
316no

Questions

What is x in 8x āˆ’ 8 = 0?

The solution of 8x āˆ’ 8 = 0 is x = 1.

How do you solve 8x āˆ’ 8 = 0?

Add 8 to both sides to get 8x = 8, then divide both sides by 8 to get x = 1.

How do I check the answer?

Replace x by 1: 8(1) āˆ’ 8 = 0, which is 0.

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