Solve 8x − 7 = 41

The solution of 8x − 7 = 41 is x = 6.

8x - 7 = 41\ \Rightarrow\ x = 6

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The lines y = 8x − 7 and y = 41 meet at x = 6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$8x - 7 = 41$
2
Add 7 to both sides:
$8x - 7 + 7 = 41 + 7 \ \Rightarrow\ 8x = 48$
3
Divide both sides by 8:
$\frac{8x}{8} = \frac{48}{8} \ \Rightarrow\ x = 6$
4
Check: put x = 6 back into the equation.
$8\cdot6 - 7 = 48 - 7 = 41 \checkmark$

LaTeX source of the formulas on this page

\[ 8x - 7 = 41\ \Rightarrow\ x = 6 \]
\[ 8x - 7 = 41 \]
\[ 8x - 7 + 7 = 41 + 7 \ \Rightarrow\ 8x = 48 \]
\[ \frac{8x}{8} = \frac{48}{8} \ \Rightarrow\ x = 6 \]
\[ 8\cdot6 - 7 = 48 - 7 = 41 \checkmark \]

Trying values of x in 8x − 7 = 41

x	8x − 7	Equals 41?
4	25	no
5	33	no
6	41	yes
7	49	no
8	57	no

Questions

What is x in 8x − 7 = 41?

The solution of 8x − 7 = 41 is x = 6.

How do you solve 8x − 7 = 41?

Add 7 to both sides to get 8x = 48, then divide both sides by 8 to get x = 6.

How do I check the answer?

Replace x by 6: 8(6) − 7 = 41, which is 41.

Solve 8x − 7 = 41

How to work it out

Trying values of x in 8x − 7 = 41

Questions

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