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Solve 8x āˆ’ 6 = āˆ’62

The solution of 8x āˆ’ 6 = āˆ’62 is x = -7.

The lines y = 8x āˆ’ 6 and y = -62 meet at x = -7-12-10-8-6-4-2-100-80-60-40-20x = -7y = 8x āˆ’ 6y = -62
The lines y = 8x āˆ’ 6 and y = -62 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’6=āˆ’628x - 6 = -62
  2. 2

    Add 6 to both sides:

    8xāˆ’6+6=āˆ’62+6 ⇒ 8x=āˆ’568x - 6 + 6 = -62 + 6 \ \Rightarrow\ 8x = -56
  3. 3

    Divide both sides by 8:

    8x8=āˆ’568 ⇒ x=āˆ’7\frac{8x}{8} = \frac{-56}{8} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    8ā‹…(āˆ’7)āˆ’6=āˆ’56āˆ’6=āˆ’62āœ“8\cdot(-7) - 6 = -56 - 6 = -62 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 6 = -62\ \Rightarrow\ x = -7 \]
\[ 8x - 6 = -62 \]
\[ 8x - 6 + 6 = -62 + 6 \ \Rightarrow\ 8x = -56 \]
\[ \frac{8x}{8} = \frac{-56}{8} \ \Rightarrow\ x = -7 \]
\[ 8\cdot(-7) - 6 = -56 - 6 = -62 \checkmark \]

Trying values of x in 8x āˆ’ 6 = āˆ’62

x8x āˆ’ 6Equals -62?
-9-78no
-8-70no
-7-62yes
-6-54no
-5-46no

Questions

What is x in 8x āˆ’ 6 = āˆ’62?

The solution of 8x āˆ’ 6 = āˆ’62 is x = -7.

How do you solve 8x āˆ’ 6 = āˆ’62?

Add 6 to both sides to get 8x = -56, then divide both sides by 8 to get x = -7.

How do I check the answer?

Replace x by -7: 8(-7) āˆ’ 6 = -62, which is -62.

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    Solve 8x āˆ’ 6 = āˆ’62: x = -7 (steps and check) | WordGPT