Solve 8x ā 6 = ā38
The solution of 8x ā 6 = ā38 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 6 to both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 8x - 6 = -38\ \Rightarrow\ x = -4 \]
\[ 8x - 6 = -38 \]
\[ 8x - 6 + 6 = -38 + 6 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) - 6 = -32 - 6 = -38 \checkmark \]Trying values of x in 8x ā 6 = ā38
| x | 8x ā 6 | Equals -38? |
|---|---|---|
| -6 | -54 | no |
| -5 | -46 | no |
| -4 | -38 | yes |
| -3 | -30 | no |
| -2 | -22 | no |
Questions
What is x in 8x ā 6 = ā38?
The solution of 8x ā 6 = ā38 is x = -4.
How do you solve 8x ā 6 = ā38?
Add 6 to both sides to get 8x = -32, then divide both sides by 8 to get x = -4.
How do I check the answer?
Replace x by -4: 8(-4) ā 6 = -38, which is -38.