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Solve 8x āˆ’ 6 = 42

The solution of 8x āˆ’ 6 = 42 is x = 6.

The lines y = 8x āˆ’ 6 and y = 42 meet at x = 62468101220406080100x = 6y = 8x āˆ’ 6y = 42
The lines y = 8x āˆ’ 6 and y = 42 meet at x = 6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’6=428x - 6 = 42
  2. 2

    Add 6 to both sides:

    8xāˆ’6+6=42+6 ⇒ 8x=488x - 6 + 6 = 42 + 6 \ \Rightarrow\ 8x = 48
  3. 3

    Divide both sides by 8:

    8x8=488 ⇒ x=6\frac{8x}{8} = \frac{48}{8} \ \Rightarrow\ x = 6
  4. 4

    Check: put x = 6 back into the equation.

    8ā‹…6āˆ’6=48āˆ’6=42āœ“8\cdot6 - 6 = 48 - 6 = 42 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 6 = 42\ \Rightarrow\ x = 6 \]
\[ 8x - 6 = 42 \]
\[ 8x - 6 + 6 = 42 + 6 \ \Rightarrow\ 8x = 48 \]
\[ \frac{8x}{8} = \frac{48}{8} \ \Rightarrow\ x = 6 \]
\[ 8\cdot6 - 6 = 48 - 6 = 42 \checkmark \]

Trying values of x in 8x āˆ’ 6 = 42

x8x āˆ’ 6Equals 42?
426no
534no
642yes
750no
858no

Questions

What is x in 8x āˆ’ 6 = 42?

The solution of 8x āˆ’ 6 = 42 is x = 6.

How do you solve 8x āˆ’ 6 = 42?

Add 6 to both sides to get 8x = 48, then divide both sides by 8 to get x = 6.

How do I check the answer?

Replace x by 6: 8(6) āˆ’ 6 = 42, which is 42.

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