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Solve 8x āˆ’ 15 = āˆ’95

The solution of 8x āˆ’ 15 = āˆ’95 is x = -10.

The lines y = 8x āˆ’ 15 and y = -95 meet at x = -10-16-14-12-10-8-6-4-140-120-100-80-60-40x = -10y = 8x āˆ’ 15y = -95
The lines y = 8x āˆ’ 15 and y = -95 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’15=āˆ’958x - 15 = -95
  2. 2

    Add 15 to both sides:

    8xāˆ’15+15=āˆ’95+15 ⇒ 8x=āˆ’808x - 15 + 15 = -95 + 15 \ \Rightarrow\ 8x = -80
  3. 3

    Divide both sides by 8:

    8x8=āˆ’808 ⇒ x=āˆ’10\frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    8ā‹…(āˆ’10)āˆ’15=āˆ’80āˆ’15=āˆ’95āœ“8\cdot(-10) - 15 = -80 - 15 = -95 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 15 = -95\ \Rightarrow\ x = -10 \]
\[ 8x - 15 = -95 \]
\[ 8x - 15 + 15 = -95 + 15 \ \Rightarrow\ 8x = -80 \]
\[ \frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10 \]
\[ 8\cdot(-10) - 15 = -80 - 15 = -95 \checkmark \]

Trying values of x in 8x āˆ’ 15 = āˆ’95

x8x āˆ’ 15Equals -95?
-12-111no
-11-103no
-10-95yes
-9-87no
-8-79no

Questions

What is x in 8x āˆ’ 15 = āˆ’95?

The solution of 8x āˆ’ 15 = āˆ’95 is x = -10.

How do you solve 8x āˆ’ 15 = āˆ’95?

Add 15 to both sides to get 8x = -80, then divide both sides by 8 to get x = -10.

How do I check the answer?

Replace x by -10: 8(-10) āˆ’ 15 = -95, which is -95.

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    Solve 8x āˆ’ 15 = āˆ’95: x = -10 (steps and check) | WordGPT