Solve 8x − 15 = 41

The solution of 8x − 15 = 41 is x = 7.

8x - 15 = 41\ \Rightarrow\ x = 7

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The lines y = 8x − 15 and y = 41 meet at x = 7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$8x - 15 = 41$
2
Add 15 to both sides:
$8x - 15 + 15 = 41 + 15 \ \Rightarrow\ 8x = 56$
3
Divide both sides by 8:
$\frac{8x}{8} = \frac{56}{8} \ \Rightarrow\ x = 7$
4
Check: put x = 7 back into the equation.
$8\cdot7 - 15 = 56 - 15 = 41 \checkmark$

LaTeX source of the formulas on this page

\[ 8x - 15 = 41\ \Rightarrow\ x = 7 \]
\[ 8x - 15 = 41 \]
\[ 8x - 15 + 15 = 41 + 15 \ \Rightarrow\ 8x = 56 \]
\[ \frac{8x}{8} = \frac{56}{8} \ \Rightarrow\ x = 7 \]
\[ 8\cdot7 - 15 = 56 - 15 = 41 \checkmark \]

Trying values of x in 8x − 15 = 41

x	8x − 15	Equals 41?
5	25	no
6	33	no
7	41	yes
8	49	no
9	57	no

Questions

What is x in 8x − 15 = 41?

The solution of 8x − 15 = 41 is x = 7.

How do you solve 8x − 15 = 41?

Add 15 to both sides to get 8x = 56, then divide both sides by 8 to get x = 7.

How do I check the answer?

Replace x by 7: 8(7) − 15 = 41, which is 41.

Solve 8x − 15 = 41

How to work it out

Trying values of x in 8x − 15 = 41

Questions

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